If it's not what You are looking for type in the equation solver your own equation and let us solve it.
12x^2+10=29x
We move all terms to the left:
12x^2+10-(29x)=0
a = 12; b = -29; c = +10;
Δ = b2-4ac
Δ = -292-4·12·10
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-19}{2*12}=\frac{10}{24} =5/12 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+19}{2*12}=\frac{48}{24} =2 $
| 63=9b-12 | | 5x+19+3x+21=180 | | 10x-8=-7x+12 | | (4x+3)+65=180 | | 19.7r-7.27=-16.3r-0.07 | | 9w-5w=16 | | 9w−5w=16 | | (3x+1)+(x+21)=180 | | -x/8=-44 | | 33x^2+42x-110.25=0 | | (3x+1)+(9x+21)=180 | | 53=-y/8 | | 5x-4+4x-2=180 | | 14=3-(2x-5) | | -15=-3(n-10) | | -4+2a=12-15a | | n/3+n/4=-7 | | 9x+8=-16 | | -15=-3(n−10) | | 42x=13x-(x-6) | | 4=w+4/3 | | -6-w=-3w+8 | | 17q-12q=5 | | 3.6=1.6-x | | -15w+17=17=15w | | 17q−12q=5 | | 4-8t=-8t+4 | | 3=t-10/3 | | -2y-3y+8=-8-5y-12 | | 6g-5=10+6g | | 3=t−10/3 | | 6g-5=1-+6g |